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Mass of sucrose C1212H2222O1111 produced by mixing 84 gm of carbon, 12 gm of hydrogen and 56 lit. O22 at 1 atm & 273 K according to given reaction, is C(s) + H22 (g) + O22 (g) →→ C1212H2222O1111(s) for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Mass of sucrose C1212H2222O1111 produced by mixing 84 gm of carbon, 12 gm of hydrogen and 56 lit. O22 at 1 atm & 273 K according to given reaction, is C(s) + H22 (g) + O22 (g) →→ C1212H2222O1111(s) covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Mass of sucrose C1212H2222O1111 produced by mixing 84 gm of carbon, 12 gm of hydrogen and 56 lit. O22 at 1 atm & 273 K according to given reaction, is C(s) + H22 (g) + O22 (g) →→ C1212H2222O1111(s).

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